Solve for x in the equation x2 + 10x+12 = 36 х = –12 оr x = 2x = -11 or x = 1x = -2 or x = 12x = -1 or x = 11

The possible answer for the above equation is x=-12 or x=2 Answer: Option 1Explanation: Given: [tex]\left[x^{2}+10 x+12\right]=36[/tex]To Find:   The possible value of x in the above equation Solution: Given equation;[tex]\left[x^{2}+10 x+12\right]=36[/tex] By using the options given the question we get Option 1; If x=-12 0r x=2 Substitute these value in the equation we get [tex]\left[(-12)^{2}+10(-12)+12\right]=36[/tex] [144-120+12]=36 [24+12]=36 36=36  Thus both the L.H.S=R.H.S Hence Option 1 gives the correct value of x Result: Thus the possible value for x in the above equation is x=-12 or x=2